Можно:
PHP код:
str tableName = 'Address';
str fieldName = 'AddrTableId';
Common common;
Query query;
QueryRun queryRun;
;
query = new Query();
query.addDataSource(tableName2Id(tableName));
queryRun = new QueryRun(query);
while (queryRun.next())
{
common = queryRun.getNo(1);
info(common.(fieldName2id(tableName2id(tableName), fieldName)));
}