PHP код:
static void Job4(Args _args)
{
COM Excel;
COM wbs;
COM wb;
COM ws;
COM r;
COM rr;
str address;
;
excel = new COM('Excel.Application');
wbs = excel.workbooks();
wb = wbs.open("C:\\Temp\\test.xls");
ws = wb.activesheet();
r = ws.range("A1:A100");
rr = r.find(2);
if (rr != null)
{
address = rr.address();
do
{
print rr.address();
rr = r.FindNext(rr);
}
while (rr != null && rr.address() != address);
}
excel.quit();
pause;
}
примерно вот так